Alien Dictionary Leetcode Problem 269 [Python Solution]
Problem Overview
In this blog post, we’re going to tackle a challenging problem known as the Alien Dictionary This problem is part of the Blind 75 list and falls under the category of Advanced Graphs.
It’s a problem that you may find quite intriguing, and we’ll walk you through the solution step by step.
Question Link: Alien Dictionary LeetCode Problem
Question:
You are faced with a new alien language that uses the Latin alphabet.
However, the order among the letters in this new language is unknown to you.
You have received a list of non-empty words from the dictionary, and these words are sorted lexicographically according to the rules of this new language.
Your task is to determine the order of the letters in this alien language.
Here are some additional details:
- You can assume that all letters are in lowercase.
- The dictionary is considered invalid if one word is a prefix of another word, and the latter appears before the former.
- If there is no valid order for the letters, you should return an empty string.
- Multiple valid orders may exist, but you should return the smallest one in normal lexicographical order.
Example:
Let’s look at an example to understand the problem better.
Suppose you are given the following list of words:
Input: ["wrt", "wrf", "er", "ett", "rftt"]
Output: "wertf"
Explanation:
- From “wrt” and “wrf”, we can deduce that ‘t’ comes before ‘f’.
- From “wrt” and “er”, we can deduce that ‘w’ comes before ‘e’.
- From “er” and “ett”, we can deduce that ‘r’ comes before ‘t’.
- From “ett” and “rftt”, we can deduce that ‘e’ comes before ‘r’.
- So, the correct order of letters is “wertf.”
Efficient Python Code Solution:
def alienOrder(self, words: List[str]) -> str:
# Create an adjacency list for characters
adj = {char: set() for word in words for char in word}
for i in range(len(words) - 1):
w1, w2 = words[i], words[i + 1]
minLen = min(len(w1), len(w2))
if len(w1) > len(w2) and w1[:minLen] == w2[:minLen]:
return ""
for j in range(minLen):
if w1[j] != w2[j]:
adj[w1[j]].add(w2[j])
break
visited = {} # {char: bool} False visited, True in the current path
res = []
def dfs(char):
if char in visited:
return visited[char]
visited[char] = True
for neighChar in adj[char]:
if dfs(neighChar):
return True
visited[char] = False
res.append(char)
for char in adj:
if dfs(char):
return ""
res.reverse()
return "".join(res)
Now, let’s break down this problem and its solution in detail.
Problem Overview
The Alien Dictionary problem is a fascinating challenge that requires determining the order of letters in an unknown alien language.
This language uses the Latin alphabet, but the order of the letters is not provided.
You are given a list of words from the dictionary, and these words are sorted according to the rules of the alien language.
Your task is to derive the correct order of letters in this alien language.
However, there are some rules and constraints to consider:
- All letters are in lowercase.
- The dictionary is considered invalid if one word is a prefix of another word, and the latter appears before the former.
- If there is no valid order for the letters, you should return an empty string.
- Multiple valid orders may exist, but you should return the smallest one in normal lexicographical order.
Understanding Constraints
Before diving into the solution, let’s clarify the constraints and challenges presented by this problem:
- The order of letters in the alien language is unknown.
- The dictionary provides words sorted based on the alien language’s rules.
- We need to extract the order of letters from the given words.
Alien Dictionary LeetCode Problem Solution
Now that we have a clear understanding of the problem, let’s explore the Python solution to the Alien Dictionary problem.
1. Bruteforce Approach
The solution starts by creating an adjacency list for characters.
This list represents the relationships between characters based on their order in the given words.
The dictionary adj
is used to store each character as a key, and the corresponding value is an empty set.
This set will be used to keep track of characters that come after the current character.
adj = {char: set() for word in words for char in word}
2. An Efficient Approach to Build Relationships
The algorithm proceeds to examine each pair of adjacent words to build the relationships between characters.
It takes the minimum length of the current and next words and compares their characters character by character.
If it finds a differing character, it adds a relationship in the adjacency list and stops comparing.
If the length of the current word is greater than the next word and their prefixes match, the dictionary is considered invalid, and the function returns an empty string.
for i in range(len(words) - 1):
w1, w2 = words[i], words[i + 1]
minLen = min(len(w1), len(w2))
if len(w1) > len(w2) and w1[:minLen] == w2[:minLen]:
return ""
for j in range(minLen):
if w1[j] != w2[j]:
adj[w1[j]].add(w2[j])
break
Time and Space Complexity
The time complexity of this solution depends on the number of characters present in the input words, as we need to traverse all the characters to build the relationships.
The space complexity is determined by the size of the adjacency list, which is also related to the number of characters.
Reasoning Behind Our Approach
This solution efficiently builds a graph that represents the relationships between characters based on the given words.
It accounts for various constraints, such as word prefixes and multiple valid orders.
By using a depth-first search (DFS) approach, it ensures that the result is derived in the correct order while detecting any loops or contradictions.
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Conclusion
In this blog post, we’ve explored the Alien Dictionary problem, a challenging graph problem from the Blind 75 list.
We’ve provided an efficient Python solution that takes into account various constraints and efficiently derives the correct order of letters in an unknown alien language.
This solution uses an adjacency list and DFS traversal to ensure accuracy and handles potential loop detection.
We hope this guide has been helpful in understanding and solving this complex problem.
If you have any questions, suggestions, or comments, please feel free to share them.
We encourage discussion and engagement with the content.
Thank you for reading!
*Note: The code provided is part of the solution for educational purposes and to help you understand the problem better